The 1948 World Series matched the Cleveland Indians against the Boston Braves. The Braves had won the National League pennant for the first time since the "Miracle Braves" team of 1914, while the Indians had spoiled a chance for the only all-Boston World Series by winning a one-game playoff against the Boston Red Sox for the American League flag. Though superstar pitcher Bob Feller failed to win either of his two starts, the Indians won the Series in six games to capture their second championship and their first since 1920 (as well as their last to the present date).
It was the first World Series to be televised on a nationwide network and was announced by famed sportcasters Red Barber, Tom Hussey (in Boston) and Van Patrick (in Cleveland). This was the second appearance in the Fall Classic for both teams, with the Indians' lone previous appearance coming in a 1920 win against the Brooklyn Dodgers and the Braves' lone precious appearance coming in a 1914 win against the Philadephia Athletics. Consequently, this was the first, and to date only, World Series in which both participating teams had previously played in, but not yet lost, a previous World Series. Currently, this phenomenon can only be repeated if either the Miami Marlins or the Arizona Diamondbacks play against either the Toronto Blue Jays or the Los Angeles Angels of Anaheim in a future World Series.
This was the only World Series from 1947 to 1958 not to feature a New York team, and also the last World Series until 1957 not won by a New York team (which the Braves won over the Yankees, after they had relocated to Milwaukee). The teams would meet again in the 1995 World Series—by that time, the Braves had moved to Atlanta.
1948 Cleveland Indians World Series Ring
- Product Code: MLB 1948
- Availability: In Stock